[PriP 1.1] Revision Tour-1 – Practical 1.1

5. What would be the output of following code?

print('doesn\'t')
print("doesn\'t")
print('"Yes,"he said.')
print("\"Yes,\"he said.")

Solution:

The provided code contains print statements with various string literals. Let’s analyze each line:

1. print('doesn\'t'): This prints the string “doesn’t” with the escape sequence \' representing a single quote. The backslash \ before the single quote escapes it, so it’s treated as a literal single quote within the string.
2. print("doesn\'t"): Similarly, this also prints the string “doesn’t” with the escape sequence \' representing a single quote.
3. print('”Yes,”he said.'): This prints the string ”Yes,”he said. with the characters ” and ” (curly double quotes) surrounding “Yes,”. Note that ” is not a regular double quote ", which may lead to unexpected output.
4. print("”Yes,”he said."): Similarly, this also prints the string ”Yes,”he said. with the characters ” and ” (curly double quotes) surrounding “Yes,”.

Let’s print each line and see the output:

print('doesn\'t')
print("doesn\'t")
print('"Yes,"he said.')
print(""Yes,"he said.")

doesn't
doesn't
"Yes,"he said.
"Yes,"he said.

In the output, the strings are printed as described above. However, note that the third and fourth lines may contain characters with curly double quotes depending on the system’s font and encoding, which may appear different from regular double quotes. But, it’s been changed here to regular double quotes only so as to avoid confusion.