[Type B] File Handling – Chapter 5 Sumita Arora
Table of Contents
14. What is the output of the following considering the given file data.csv.
File data.csv contains:
Identifier;First name;Last name
901242;Riya;Verma
207074;Laura;Grey
408129;Ali;Baig
934600;Manit;Kaur
507916;Jiva;Jain
import csv
with open('C:\data.csv','r+') as f:
data = csv.reader(f)
for row in data:
if 'the' in row:
print(row)
Answer: The code with the provided data.csv content will produce no output.
The given code snippet attempts to read the CSV file data.csv
and print any row that contains the string ‘the’. However, in the current form, this code will not print any rows because the CSV data does not contain the string ‘the’.
There’s an error in the code too which also prevents the correct display of output.
Explanation:
- Delimiter Mismatch: While the code uses a comma (“,”) as the delimiter in
csv.reader()
, the data.csv file actually uses a semicolon (“;”) as a delimiter. This mismatch leads to incorrect splitting of the rows. - Therefore, even if the data.csv contains rows where “the” is present within individual fields (e.g., “Riya likes the book”), the code won’t identify them due to the delimiter mismatch.
To achieve the intended output of printing rows containing “the,” you need to correct the delimiter in the csv.reader()
function:
import csv
with open('C:\data.csv', 'r+') as f:
data = csv.reader(f, delimiter=";") # Use semicolon as the delimiter
for row in data:
if 'the' in row:
print(row)
With this correction, the code will split the rows based on the semicolon, allowing it to correctly identify and print rows containing “the”.
However, since the provided CSV data does not contain the string ‘the’, the output of this modified code will still be empty.
Good work posting these questions in detail!